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How do you find the distance from two points to the line of an equation?
Tuckerallen27
It is the square root of (x1-x2)^2 + (y1-y2)^2
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∙ 9y ago
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Why do you need to find the equation of a line?
So that you can plot out the points of a straight line on graph paper.
What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
What are points on a line for geometry?
In coordinated geometry the points on a straight line will determine its equation.
What does the line represent when you graph a linear equation?
It is the locus of all points whose coordinates satisfy the equation of the line.
How do you find the slope of a line from its graph what is the formula for m?
The slope of a line is the rise divided by the run. In other terms, if, X = the horizontal distance between two points on a line and Y = the vertical distance between the same points, then m = Y/X
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Why do you need to find the equation of a line?
So that you can plot out the points of a straight line on graph paper.
Find the equation of the line containing the two points shown?
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
What is the equation of the line that contains the points -32 and 5-5?
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
How can you find equation of the line passing thruogh two points?
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
What are points on a line for geometry?
In coordinated geometry the points on a straight line will determine its equation.
How can you find an equation line between two pair of points?
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
What is the input-output rule for the points on the line?
The answer will depend on the equation of the line.
How can an absolute value equation help you calculate the distance form one point to another on the coordinate plane when the points are on the same vertical line?
The absolute difference in the vertical direction is zero but the absolute difference in the horizontal direction will be the horizontal distance - which is the distance between the points.
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates?
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
