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Hey guys....

There is no correct simple general formula for sum to n terms of the series

1+1/2+1/3+1/4+ ............. + 1/n

The following expression is relatively a very good approximation.

S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)

Deviation from the actual value fluctuates but remains relatively low.

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āˆ™ 13y ago
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āˆ™ 1mo ago

The sum of n terms in a harmonic progression is given by the formula ( S_n = \frac{n}{a_1+ \frac{ (n-1)d}{2}} ) where ( S_n ) is the sum of n terms, ( a_1 ) is the first term, d is the common difference.

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Q: How do you find the sum to n terms of a harmonic progression?
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