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How do you find the sum to n terms of a harmonic progression?
Wiki User
ā 13y ago
Hey guys....
There is no correct simple general formula for sum to n terms of the series
1+1/2+1/3+1/4+ ............. + 1/n
The following expression is relatively a very good approximation.
S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)
Deviation from the actual value fluctuates but remains relatively low.
Wiki User
ā 13y ago
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Write a C program to accept the elements of a 3 x 3 matrix and find its sum of the major diagonal elements The program should print the given matrix along with its sum of the major diagonal elements?
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2
Formula to find out the sum of n terms?
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
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An arithmetic series is the sum of the terms in an arithmetic progression.
Who gave the formula for finding sum of the first 'n' terms in Arithmetic Progression?
RAMANUJANRAMANUJAN
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This question is impossible to answer without knowing the difference between successive terms of the progression.
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A geometric progression has a common ratio -1/2 and the sum of its first 3 terms is 18. Find the sum to infinity?
The sum to infinity of a geometric series is given by the formula Sā=a1/(1-r), where a1 is the first term in the series and r is found by dividing any term by the term immediately before it.
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The sum of the 1st n terms is : N(3N-1)/2 Explanation : The sum from 1 to N of (3m-2) = 3 * sumFrom1toN(m) - sumFrom1toN(2) = 3 * (N*(N+1)/2) -2*N = N(3N-1)/2 For N=10 => 145
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4
