It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
The given series appears to follow a pattern where each term can be expressed in the form of a quadratic sequence. The nth term can be represented as ( a_n = n(3n - 2) ). To find the sum of the first n terms, ( S_n ), we can derive it from the formula for the sum of a quadratic sequence, leading to ( S_n = \frac{n}{6}(n + 1)(n + 2) ). Thus, the sum to n terms of the series is given by this formula.
Find the Sum to n terms of the series 5 5+55+555+ +n Terms
n*(n+1)
There is no formula that will sum n even numbers without further qualifications: for example, n even numbers in a sequence.
You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
The formula to find the sum of a geometric sequence is adding a + ar + ar2 + ar3 + ar4. The sum, to n terms, is given byS(n) = a*(1 - r^n)/(1 - r) or, equivalently, a*(r^n - 1)/(r - 1)
The formula for the sum of the first n terms of an arithmetic progression is Sn = n/2 * (a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term.
The given series appears to follow a pattern where each term can be expressed in the form of a quadratic sequence. The nth term can be represented as ( a_n = n(3n - 2) ). To find the sum of the first n terms, ( S_n ), we can derive it from the formula for the sum of a quadratic sequence, leading to ( S_n = \frac{n}{6}(n + 1)(n + 2) ). Thus, the sum to n terms of the series is given by this formula.
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
The formula for calculating the Gauss sum from 1 to 100 is n(n1)/2, where n is the number of terms in the sequence.
Find the Sum to n terms of the series 5 5+55+555+ +n Terms
Hey guys....There is no correct simple general formula for sum to n terms of the series1+1/2+1/3+1/4+ ............. + 1/nThe following expression is relatively a very good approximation.S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)Deviation from the actual value fluctuates but remains relatively low.
n*(n+1)
There is no formula that will sum n even numbers without further qualifications: for example, n even numbers in a sequence.
The formula to find the sum of interior angles of a polygon is 180° × (n - 2), where n is the number of sides of the polygon.
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