(1 + 25) x 25/2 ie 425.
The sum of the first n integers is (n + 1) x n/2
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
The sum of the first 25 prime numbers is 1,060.
The sum of number and four times a number is 25 write in algebraic expression
The sum of the first 25 prime numbers is 1,060.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
The sum of the first 5,000 odd numbers is 25,000,000 (25 million). This is an easy calculation. Simply square the number of integers you are looking to calculate. In this case 5,000 squared = 5,000 x 5,000 = 25 million.
25 + 25 = 50
If their difference is 25 then the larger number is the smaller number plus 25. Let the smaller number be x then the larger number is x + 25 → their sum is x + (x + 25) = 81 → 2x = 56 → x = 28 → the two numbers are 28 and 53.
-25 + (-2) = 3
625
975
Yes 16+9=25