975
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10+20+30 = 60
Oh, what a happy little question! To find the sum of the first 500 multiples of 3, we can use the formula for the sum of an arithmetic series: (n/2) * (first term + last term). In this case, the first term is 3 and the last term is 3 * 500. Plugging these values in, we get (500/2) * (3 + 1500) = 250 * 1503 = 375,750.
The first 50 multiples of 6 are the first fifty even multiples of 3.
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.