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Yes, when the inequality has a less that or equal to sign, or a greater than sign or equal to sign, then the equal sign can be replaced and get a solution that is common to both the equation and the inequality. There can also be other solutions to the inequality, where as the solution for the equation will be a valid one.
x+7 is greater than or equal to 2
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
x ≤ -sqrt(11) or x ≥ sqrt(11)
An inequality has no magnitude. A number can be greater than or equal to -5, but not an inequality.
Yes, but only when the inequality is not a strict inequality: thatis to say it is a "less than or equal to" or "more than or equal to" inequality. In such cases, the solution to the "or equal to" aspect will satisfy the corresponding inequality.
+sqrt(7) = 2.6457 (approx) so the solution is-2.6457 < x < 2.6457
an inequality
The line is dotted when the inequality is a strict inequality, ie it is either "less than" (<) or "greater than" (>). If there is an equality in the inequality, ie "less than or equal to" (≤), "greater than or equal to" (≥) or "equal to" (=) then the line is drawn as a solid line.
No. To be an inequality, it must somewhere have a greater than, less than, greater-or-equal, or less-or-equal sign.
I think that you are asking about the linear inequalities with two variables, so my answer is related to them. First, you have to draw the boundary line (be careful, if your inequality does not contain the equal sign, the boundary line will be a dashed line, because the points on the line are not solutions to the inequality), which divide the coordinate system in two half-planes. Second, you have to test a point on either sides of the line (the best point is the origin, (0, 0), if it is not on the boundary line). If that point satisfies the inequality, then there are all its solutions, otherwise they are to the opposite side.
No. An inequality will show two expressions that aren't equal.