5∫10[1/√(x2 - 9)] dx = 5∫10[dx/√(x2 - 32)]
Let x = 3 sec θ, where 0 < θ < π/2 or π < θ < 3π/2. Then, dx = 3 sec θ tan θ dθ and
√(x2 - 9) = √[(3 sec θ)2 - 9] = √[9(sec2 θ - 1)] = √(9 tan2 θ) = 3 tan θ
5∫10[dx/√(x2 - 32)]
= 5∫10[(√3 sec θ tan θ)/(3 tan θ)] dθ
= 5∫10 sec θ dθ
= ln |sec θ + tan θ|5|10 = ln sec 10 + tan 10 - sec 5 - tan 5 = -2.298
If it was for example: 50,000 meters squared ± 50. That means that the land could be between 49,950 and 50,050. So the ± is just telling you the limits.
It's about 34 and a third
2x squared minus 4
No, unless "a" happens to be equal to 0, or to 1.
hello
If it was for example: 50,000 meters squared ± 50. That means that the land could be between 49,950 and 50,050. So the ± is just telling you the limits.
It's about 34 and a third
3x squared minus 25x minus 28
n squared minus n
2x squared minus 4
No, unless "a" happens to be equal to 0, or to 1.
-22 - -22
x = ? 42 = x squared minus x
hello
(9y+2z)(y-3z)
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
sin squared