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(1-cosx)/sinx + sinx/(1- cosx)

= [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)]

= [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)]

= [2 - 2cosx]/[sinx*(1-cosx)]

= [2*(1-cosx)]/[sinx*(1-cosx)]

= 2/sinx

= 2cosecx

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Q: How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
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