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Use this identity

sin2x+cos2x=1

sin2x=1-cos2x

so

sin2x/(1-cosx)

=(1-cos2x)/(1-cosx)

=(1-cosx)(1+cosx)/(1-cosx)

=1+cosx

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โˆ™ 2011-02-24 03:31:53
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How do you solve sin squared x divided by 1 - cos x?
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