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How do you solve 2x minus 3 all over the square root of x plus 2 when 2 is not under the root and that all equals the square root of x?
Kiwi215
To solve this expression for x:
(2x - 3) / (√x + 2) = √x
We'll first multiply both sides by the denominator on the left:
2x - 3 = x + 2√x
Then subtract x from both sides:
x - 3 = 2√x
Move all terms to the same side:
x - 2√x - 3 = 0
Now we can factor the expression, realizing that x is the square of √x:
(√x - 3)(√x + 1) = 0
Giving us our answers:
x ∈ {9, 1}
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∙ 12y ago
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