One easy way to solve this would be to use the quadratic formula, x=(-b+/-sqrt(b^2-4*a*c))/2a. In this case, the formula is x=(-5+/-sqrt(25-4*3*8))/6. In this case, however, the number under the square root is negative, and so the equation has no real solutions.
Improved Answer:-
3x2+5x-8 = 0
(3x+8)(x-1) = 0
x = -8/3 or x = 1
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The discriminant b2-4ac is -23
104
irdk
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
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X=1
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
a^(2) - b^(2) + ac - bc Factor ( a - b)( a + b) + c(a - b) Factor further (a - b)(a + b + c) Done!!!!!
x = 25 / 3squared + 5
You have to put your heart into it!
It can be solved by using the quadratic equation formula.
(b-4) squared
2
All the time
Factor it. (x - 8)(x - 2) x = 2, 8
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.