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Restate the question: Solve for y: 2y = y+2
Subtract y from both sides: 2y-y = y-y+2 <=> y=2
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
5+y+2y? = 5+3y?
2y + 7x + y-1?
9+2y=3 2y=-6 y=-3
2y = 4 (divide both sides by 2 to solve) y = 2
(2y + 1) + (y^2 + 1) = 2y + 1 + y^2 + 1 = y^2 + 2y + 2
√(2y) + 3 = 11 √(2y) = 11 - 3 = 8 √2 x √y = 8 √y = 8/√2 y = (8/√2)2 = 64/2 = 32
6x+2y=4 gives y=2-(1/3)x
2y
3x+2y=6 2y=-3x+6 y=-1.5x+3
2y = 15 y = 15/2 y = 7.5