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How do you solve 3x squared plus 10 x plus 8 equal 0 A equals 3 B equals 10 and c equals 8?
Wiki User
∙ 12y ago
As your question implies, the quadratic formula. You know your a,b and c already.
X = - b (+/-) sqrt(b2- 4ac)/2a
X = - 10 (+/-) sqrt[102 - 4(3)(8)]/2(3)
X = - 10 (+/-) sqrt(100 - 96)/6
X = - 10 (+/-) sqrt(4)/6
X = [- 10 (+/-) 2]/6
---------------------------
X = - 4/3
and
X = - 2
Wiki User
∙ 12y ago
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