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Q: How do you solve 3y plus 8 equals 3?

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(3,3)

Yes and it works out that x = 3 and y = 4

Divide all terms by -3 then it will be in slope intercept form

4x + 3y = 7 y = [(-4)/3] x + 7/3

To solve an equation with three unknowns, x, y and z, you require 3 independent equations.

2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9

3y=ab. Divide by 3 to get y=ab/3

7y = 3y - 12 4y = -12 y = -3

x = 3 and y = 0

x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5

3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8

It works out that x = 6 and y = 3 or as (6, 3)

If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.

2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6

It is [4m-1, (4m-2)/3]

2x + 3y = 12 x = 1.45, so 2 * 1.45 + 3y = 12 2.9 + 3y = 12 3y = 12 - 2.9 = 9.1 y = 9.1/3 = 3.0333... or 91/30 or 3 1/30.

x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5

(3, 2) because x = 3 and y = 2

(-1, 0)

y = -1

4x+3/3=y

Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?

n=3,y=4 2(n+3y)=30

y=5x+2 if y equals -4

x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.