2x+3y=13 3x-y=3 x=2
4x+3/3=y
x = 3, y = 3
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
(3,3)
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Yes and it works out that x = 3 and y = 4
7y = 3y - 12 4y = -12 y = -3
4x + 3y = 7 y = [(-4)/3] x + 7/3
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
Divide all terms by -3 then it will be in slope intercept form
Solve for y 3y=-7x+9 y=-7/3x+3 the slope is the coefficient of x in this case, it is -7/3
2x + 3y = 12 x = 1.45, so 2 * 1.45 + 3y = 12 2.9 + 3y = 12 3y = 12 - 2.9 = 9.1 y = 9.1/3 = 3.0333... or 91/30 or 3 1/30.
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
2x + 3y = 11Subract 2x from each side:3y = 11 - 2xDivide both sides by 3:y = 11/3 - (2/3)x
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.