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First, I am assuming you mean P = 2L + 2W, solve for W. If so, then see below!
You solve equations the same way, whether they have multiple variables or not:
Distribute, Combine Like Terms, Move the variable you are isolating to one side, Add or Subtract, then Multiply or Divide.
Let's show how this equation is very much like an equation having only one variable:
28 = 20 + 2W
-20 -20
8 = 2W
÷2 ÷2
4 = W
So, if you get stuck, just "fake" the variables you aren't solving for into being random numbers. Solve your "fake" equation like you would any equation. Then use the same steps in your original "variable" equation.
P = 2L + 2W
-2L -2L
P-2L= 2W
÷2 ÷2
(P-2L)/2 = W
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∙ 12y ago
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P2L 2w is the formula for what?
The equation is P=2L * 2WWhich stands for Perimeter=2(length) * 2(width)
Solve for x P equals 2x plus 2w?
x = (P - 2W) / 2
How do you solve this equation- 3w 419-2w?
That's not an equation. It need a = sign before you can solve it. However you can simplify it by combining like factors
How do you solve 8w-8-6w4w-7?
Combine like terms: 8w-6w = 2w -8-7 = -15 6w4w = 24w2 So, your expression is now: 24w2 + 2w - 15
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
What is 5-32 plus 2w equals -7?
Using basic algebra we can solve this problem. First we need to write out the problem:5-32+2w = -7-27+2w = -72w = 20w = 10
Solve for w 2l plus 2w equals P?
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
The length of a garden is 2 times the width The perimeter of the graden is 144ft Write and solve an equation to find the length and the width of the garden?
length = 48, width = 24 l = 2w 2l + 2w = 144 2l + 2w = 144 2(2w) + 2w = 144 4w + 2w =144 w = 144/6 w = 24 l = 2w l = 2(24) l = 48
How do you solve 2w plus 16 equals -6w minus 8?
2w + 16 = - 6w - 8 2w + 16 + 6w = - 8 8w + 16 = - 8 8w = - 8 - 16 8w = - 24 w = - 3
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
22
Solve for 4w2-2 equals -7w?
4w - 2 = -7w11w - 2 = 011w = 2w = 2/11
The length of rectangle is 5 less than twice the width The perimeter of the rectangle is 80. Find the dimensions of the rectangle?
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
