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The formula for the perimeter of a rectangle is P equals 2W plus 2L with perimitor of 100 length 30?
P = 100 l = 30 w = 20
5w plus 2 equals 2w plus 5?
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
Write the perimeter of a rectangle?
p=2l+2w
What is the variable and constant in P equals 2W 2L?
'W' and 'L' are independent variables. 'P' is the dependent variable. '2' and '2' are the constants.
How big is a 12 by 12 room?
To solve for area: A=lw (Area equals length times width) The length and width are both 12. Substitute 12 for l and w. A=12x12 Multiply. A=144 The room has an area of 144 units. To solve for perimeter: P=2l+2w (Perimeter equals two time the length plus two times the width). Substitute 12 for l and w. P=(2x12)+(2x12) Simplify. P=24+24 P=48 The room has a perimeter of 48 units.
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
22
Solve for x P equals 2x plus 2w?
x = (P - 2W) / 2
Formula for length of a rectangle?
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
Work this problem Given P equals 2l plus 2w close parenthesis solve for B Put answer in form of isolated variable formula?
There is no indication as to what B represents and consequently no possibility of answering the question.
What happens to the perimeter of a rectangle when you double one of its dimensions?
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).
How do you solve questions like P2L 2W solve for W?
First, I am assuming you mean P = 2L + 2W, solve for W. If so, then see below! You solve equations the same way, whether they have multiple variables or not: Distribute, Combine Like Terms, Move the variable you are isolating to one side, Add or Subtract, then Multiply or Divide. Let's show how this equation is very much like an equation having only one variable: 28 = 20 + 2W -20 -20 8 = 2W ÷2 ÷2 4 = W So, if you get stuck, just "fake" the variables you aren't solving for into being random numbers. Solve your "fake" equation like you would any equation. Then use the same steps in your original "variable" equation. P = 2L + 2W -2L -2L P-2L= 2W ÷2 ÷2 (P-2L)/2 = W
The formula for the perimeter of a rectangle is P equals 2W plus 2L with perimitor of 100 length 30?
P = 100 l = 30 w = 20
What is 5-32 plus 2w equals -7?
Using basic algebra we can solve this problem. First we need to write out the problem:5-32+2w = -7-27+2w = -72w = 20w = 10
The length of a garden is 2 times the width The perimeter of the graden is 144ft Write and solve an equation to find the length and the width of the garden?
length = 48, width = 24 l = 2w 2l + 2w = 144 2l + 2w = 144 2(2w) + 2w = 144 4w + 2w =144 w = 144/6 w = 24 l = 2w l = 2(24) l = 48
What is the formula for perimeter of a rectangle?
For a rectangle, P = 2L + 2W (L is length, W is width)
What is the dimensions of a rectangle if the length is 4 centimeters less than twice its width and the perimeter is 34 centimeters what is the dimensions of a rectangle?
you have two equations with two unknowns, length and width let W = width and L = length 2W - 4 = L (1) The perimeter is 2L + 2W 2L + 2W = 34 (2) rearrange (1) and (2) 2W - L = 4 2W +2L = 34 multiply (1) both sides by 2 4W - 2L = 8 2W + 2L =34 add equations 6W = 42 W = 7 solve L from (2) by substituting W = 7 L = 10
