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Q: How do you solve the equation Factorise x3 4x?

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1

It is a cubic equation in the variable x.

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

-24

x3+xy-x2y2=x(x2+y-xy2)

5x2-8x-4

Since that isn't an equation, there is really nothing to solve.

Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)

55846.2365

x3-y3

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