Q: How to factorise X to the power of 5 - 4x squared?

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5

-5

(4x-5)(4x+5)

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It is (x+5)(x+1) when factored

(4x + 5)(x - 3)

16x^2 - 25 Recognise that both 16 and 25 are squared numbers, 16 = 4^(2) & 25 = 5^(2) Substituting 4^(2)x^(2) - 5^(2) = > (4x)^(2) - 5^(2) We now have two squared terms with a negative between them. NB two squared terms with positive does NOT factor. Factoring (4x - 5)(4x + 5)

8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)

2(2x-11)(3x+5)

1

It is: (x-5)(x+1) when factored

Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)