answersLogoWhite

0


Best Answer

Sin(2x) = -cos(x)

But sin(2x) = 2 sin(x) cos(x)

Substitute it:

2 sin(x) cos(x) = -cos(x)

Divide each side by cos(x):

2 sin(x) = -1

sin(x) = -1/2

x = 210°

x = 330°

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you solve the trigonomic equation sin2x equals negative cosx?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the differential equation of y equals sin2x?

dy/dx = 2cos2x


Is sin2x equal to sin2x?

sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!


Sin Squared x plus cos x equals 0 for x is a part of 1 to 360 degrees?

Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.


Sin2x - radical 2 cosx equals 0?

Sin2x = radical 2


How does 1 plus cot squared x equals csc squared x?

The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.


Why does -2sinxcosx equal -sin2x?

-4


How do you solve 2 cos squared x - sinx - 1?

1


How do you find sin theta when tan theta equals one fourth?

I will note x instead of theta tan(x) = sin(x) / cos(x) = 1/4 sin(x) = cos(x)/4 = ±sqrt(1-sin2x)/4 as cos2x + sin2 x = 1 4 sin(x) = ±sqrt(1-sin2x) 16 sin2x = 1-sin2x 17 sin2x = 1 sin2x = 1/17 sin(x) = ±1/sqrt(17)


Are there any functions whose sum of squares equals 1?

cos2x + sin2x = 1; cosh2x + sinh2x = 1.


How do you prove one - tan square x divided by one plus tan square xequal to cos two x?

(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)


How do you solve sin2x plus 3 cos 2x equals 0?

sin2x + 3*cos2x = 0sin2x = -3*cos2xtan2x = -32x = arctan(-3)x = 0.5*arctan(-3) in the domain which should have been specified. As none has, the question has no answer.


Can you prove that cossquaredx - sinsquaredx equals 2cossquaredx -1?

3