Sin(2x) = -cos(x)
But sin(2x) = 2 sin(x) cos(x)
Substitute it:
2 sin(x) cos(x) = -cos(x)
Divide each side by cos(x):
2 sin(x) = -1
sin(x) = -1/2
x = 210°
x = 330°
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dy/dx = 2cos2x
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)
Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x
sin2x because sin2x + cos2x = 1