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How do you solve this math problem a squared plus 2a minus 15 equals 0?
Nikkole2011
a2 + 2a - 15 = 0
This can be factorised:
a2 + 2a - 15 = (a - 3)(a + 5) = 0
So a = 3 and -5.
A more robust way is to shove it into the general solution:
If αx2 + βx + η = 0, then x = (-β ± √(β2 - 4αγ)) / 2α
So if a2 + 2a - 15 = 0, then:
a = (-2 ± √(22 - 4*1*-15)) / 2*1
a = (-2±√(64))/2 = (-2±8)/2
a = -10/2, 6/2
a = -5, 3
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