Best Answer

(x-3)/4 = 10

Multiply each side by 4:

x - 3 = 40

Add 3 to each side:

x = 43

Q: How do you solve x-3 divided by 4 equals 10?

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Realising that 125 is a perfect cube, this is actually pretty easy: x3 + 125 = 0 x3 = -125 x = -5

x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

2x2-y2

10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4

Related questions

(10-4/2)x3=24

cube root of 216 = 6 > X= 6

Realising that 125 is a perfect cube, this is actually pretty easy: x3 + 125 = 0 x3 = -125 x = -5

x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4

(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

1.6667

2x2-y2

X3xX4=X3+4=X7 this is the correct answer.

3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)

5x3 = 320 x3 = 320/5 = 64 So x = cuberoot(64) = 4

10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4