x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
2x2-y2
10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4
x3-4=2 Add four to both sides. x3=6 Take the cu=6 be root of both sides. x is equal to the cube root of 6, or approximately 1.81712.
(10-4/2)x3=24
cube root of 216 = 6 > X= 6
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
2x2-y2
3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)
5x3 = 320 x3 = 320/5 = 64 So x = cuberoot(64) = 4
1.6667
10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4
x3-4=2 Add four to both sides. x3=6 Take the cu=6 be root of both sides. x is equal to the cube root of 6, or approximately 1.81712.
x3 6x2-x-30