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Assuming that is:
x - √x = 6
rearrange to make the √x the subject:
√x = x - 6
Square both sides:
x = x2 - 12x + 36
Rearrange into normal quadratic form and solve:
x2 - 13x + 36 = 0
→ (x - 9)(x - 4) = 0
→ x = 9
or x = 4
However, note that this second one gives √x = - 2, but the radical √x is usually taken to mean the positive root of x, thus x = 9 is the solution.
What else can I help you with?
Can you solve x squared minus 4x minus 2 equals 0?
Yes and x = 2+square root of 6 or x = 2-square root of 6
What number adds together to give -8 and multiple together to give 6?
Let's x be one of the numbers, and y the other number. So, x + y = -8 xy = 6 y = -x - 8 x(-x -8) = 6 -x^2 - 8x = 6 multiply by -1 both sides x^2 + 8x = -6 solve for x by completing the square; x^2 + 8x + 16 = -6 + 16 (x + 4)^2 = 10 x + 4 = square root of 10 x = -4 + square root of 10 or x = -4 - square root of 10 if we continue to solve the system of the equations, we can find the same value for y. Thus the numbers are -4 + square root of 10 and -4 - square root of 10. Check: (-4 + square root of 10) + (-4 - square root of 10) = -4 + square root of 10 - 4 - square root of 10 = -8 (-4 + square root of 10)(-4 - square root of 10) = (-4)^2 - (square root of 10)^2 = 16 - 10 = 6
What is the principal square root by simplifying the radical 24?
The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).
What is the square root of 6 the Square root of 6 to infinity?
take x = root 6+ root 6.............upto infinityx = root 6 + x ........ie take root six once and keep the n number of root 6 as xsquare on both sidesx2 = 6 + xx2 - x- 6 = 0 solve this quadratic equations.you will get x= 3 or -2but x is not -2 as it will not satisfyso x = 3thus the valueroot 6 plus root 6 till infinity = 3
Solve this quadratic equation using the quadratic formula x2 - 6x 6 0?
if this is x squared -6x+6=0 then -6=b, a=1, c=6 6+ square root of -6 squared-4(6x1) - 6+ square root of (36-24) - 6+ square root of 12 - 6+ square root of 4 x square root of 3 - 6 + (2x square root of 3) - that is all divided by 2 multiplied by a meaning it is divided by 2. so x= 6 + or - (2 square root 3) divided by 2 srry steps are jmbled -
How do you solve for x when it equals the square root of y to the fourth minus y?
If x equals the square root of ...., then you already have solved for x
solve for X x2 plus x plus 6?
x = -0.5 + 2.397915761656359ix = -0.5 - 2.397915761656359iwhere i is the imaginary square root of negative one.
What is the square root of 2 multiplied by the square root of 18?
Several different ways in which the solution can be expressed. 2 √18 Take everything inside the square root. 2√18 = √(4 x 18) = √72 Simplify the square root. 2√18 = 2√(9 x 2) = 2 x 3√2 = 6√2 Solve the square root. 2√18 = 2 x 4.24264 = 8.48528 (5dp)
What is the answer to 4 square root 25 x square root 120?
To solve this problem, you must first solve the smaller problems. The square root of 25 is 5, and the square root of 120 is 10.95. First solve the equation on the left side of the multiplication sign, which is 4 x 5. Now, multiple the answer of 20 by 10.95, which is 219.
How do you find the square root of 6 times the square root of 24?
Oh, dude, finding the square root of 6 times the square root of 24 is like finding out what's inside a mystery box. You simply multiply the numbers under the square roots together, so it's the square root of 144. That simplifies to 12, because 12 times 12 is 144. Easy peasy, lemon squeezy!
Can you solve x squared plus x minus six equals zero?
x2 + X -6 =0 so X2 + X = 6 so X2 = 6-x so X = square root of (6-x) That's as far as I can get it.
X2-6x plus 1 equals 0?
x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
