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How do you solve x squared plus 3x minus 10 greater than or equal 0?
Wiki User
∙ 11y ago
x2 + 3x - 10 ≥ 0
The equivalent quadratic equation is
x2 + 3x - 10 = 0
(x + 5)*(x - 2) = 0
and the solutions are x = -5 and x = 2.
Since the coefficient of x2 is positive, the solution is the disjoint region outside the roots of the equivalent quadratic equation.
Therefore, x ≤ -5 or x ≥ 2
Wiki User
∙ 11y ago
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