if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
Divide the rectangle in two triangles and then use the pythagorean theorem to find the remaining sides.
you use the Pythagorean theorem. a^2+b^2=c^2
If they are the dimensions of a rectangle then use Pythagoras' theorem to find the length of the diagonal.
The answer depends on what information is provided: the volume, total surface area, principal diagonal, minor diagonal, etc.
The square has a diagonal measurement of: 1.13 km
A diagonal is a line so the area of any diagonal must be zero.
Use Pythagoras' theorem to find the length of the diagonal in the square
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If you have the lengths of the two sides and a diagonal, then you can use Heron's formula to find the area of one triangle and double it for the area of the parallelogram.If you have two sides and an angle, then area = a*b*sin(C).
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49