The diagonal of a 101 inch square is about 142.84 inches.
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.
a square's sides are equal. so area = (length of side)2 = 33 inches so sqrt(33) = length of side length of side = 5.744....inches = 5.7 inches (to the nearest tenth of an inch)
The diagonal of a 101 inch square is about 142.84 inches.
The diagonal is 517.602 inches.
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
33" * 33" = 1089 sq inches.
About 21.2 inches.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
A square with 2-inch sides has a diagonal of: 2.828 inches.
Approximately 35.35 inches
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal of a 20 inch square is the square root of 800 inches, approximately 28.284 inches, which is the sum of the squares of two sides.
Side = sqrt(72) inches = 8.49 in approx.
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in