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Q: How do you write 7r in commutative property of addition?

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7r-43 = -36

how do i solve -3r+3r=-6(7+7r)-7(4-7r)

100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8

12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14

I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]

2r + 7r - 6t - r + 7t = 8r + t

7 × (r + 8) = 7(r + 8) = 7r + 56

63

if the x in the formula means multiply (next time please use * to denote multiplication) then: 7r-38

If that's the equation 6r + 7 = 13 + 7r, r = -6

7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13

The answer is -r

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