If that's the equation 6r + 7 = 13 + 7r, r = -6
-20 + 13 = -7
13 x (15 + 7) ie 13 x 22 = 286 or 13 x 15 = 195, 13 x 7 = 91, 195 + 91 = 286
yes.
you need to reorder the problem by manipulating the numbers -2x-7=-x+13 group your variables and constants thus -x-2x=7+13 simplify -3x=20 simplify again x=-20/3
well... order of operations... says 7 + (2x3) - (5x2) which is 7 + 6 - 10 simplified as 13 - 10
r2+6r-7 = (r+7)(r-1) when factored
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
-6r-5 = 7-12r 12r-6r = 7+5 6r = 12 r = 2
7 times some other unknown number then add 8
7(r-12) A 7 is taken out because it is a common factor to both terms.
7 × (r + 8) = 7(r + 8) = 7r + 56
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
- 6r - 5 = 7 - 12r add 12r to both sides 12r - 6r - 5 = 7 - 12r + 12r 6r - 5 = 7 add 5 to both sides 6r - 5 + 5 = 7 + 5 6r = 12 divide both side integers by 6 r = 2 ---------- check in original equation -6(2) - 5 = 7 - 12(2) - 12 - 5 = 7 - 24 - 17 = - 17 checks
yes it is
13 + 23 + 12 + 7 = 55
13 + 21 - 7 + 12 = 15
To solve the equation (100 \cdot 7r = 44), first divide both sides by 100, yielding (7r = \frac{44}{100}). Simplifying the right side gives (7r = 0.44). Finally, divide both sides by 7 to find (r = \frac{0.44}{7}), which equals approximately (0.062857). Thus, (r \approx 0.0629).