to solve ax2 + bx + c use the quadratic formula:
(-b +/-(b2 - 4ac))/2a.
Programming this should be a doddle.
You substitute the value of the variable into the quadratic equation and evaluate the expression.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
Vertices in quadratic equations can be used to determine the highest price to sell a product before losing money again.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
-9
If the quadratic is ax2 + bx + c = 0 then the product of the roots is c/a.
the sum is -b/a and the product is c/a
You substitute the value of the variable into the quadratic equation and evaluate the expression.
If the discriminant of a quadratic equation is less than zero then it will not have any real roots.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
Vertices in quadratic equations can be used to determine the highest price to sell a product before losing money again.
In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.
Whenever there are polynomials of the form aX2+bX+c=0 then this type of equation is know as a quadratic equation. to solve these we usually break b into two parts such that there product is equal to a*c and I hope you know how to factor polynomials.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
-9
19
The numbers are 15.75 and -5.75 When tackling probiems like this form a quadratic equation with the information given and solving the equation will give the solutions.