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Equation of any circle, with any radius, and its center at any point:
[ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
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How do you write the equation of a circle?
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
What is the equation of the circle with center (-3.2 -2.1) and radius 4.3?
The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49
How do you find the radius and the coordinates of the center for each circle?
The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.
What is the equation of the circle that touches the x axis when its center is at 2 5?
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
How do you write the equation of a circle?
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
What is the equation of the circle with center 2 9 and radius 7?
depends on the equation.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
What is the equation for a circle with a center of (0 0) and a radius of 9?
The equation of the circle is: x^2 + y^2 = 81
Write the equation of circle if the center of a circal is 6 and -5 and redius is 4?
(x - 6)2 + (y + 5)2 = 16
How do you write an equation in standard form of a circle?
(x - h)2 + (y - k)2 = r2 where h is the x coordinate of the center of the circle. where k is the y coordinate of the center of the circle. where x is the x coordinate of point (x,y) on the edge of the circle. where y is the y coordinate of point (x,y) on the edge of the circle. Additional assistance here: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php
What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
How do you get the formula center of curvature?
This starts with the collocation circle to go through the three points on the curve. First write the equation of a circle. Then write three equations that force the collocation circle to go through the three points on the curve. Last, solve the equations for a, b, and r.
What is the equation of the circle with center (-3.2 -2.1) and radius 4.3?
The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49
What is the equation of the circle with center (2 -9) and radius 7?
Equation of circle: (x-2)^2 +(y+9)^2 = 49
