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How many times can you arrange the letters in maths?
25 times
How many ways can you arrange the letters in the word BUBBLE?
36 times
How many ways can you arrange the letters in the word FROG?
24 times
How many times can you re-arrange the letters in this word RANDOM?
There are 720 possible permutations.
How many times can the letters of CANADA be arranged?
There are 6 letters so there are 6P6 or 720 ways to arrange them. They don't all make a real word though.
How many ways can you arrange the letters a b c d?
5 x 4 x 3 x 2 = 120 different ways to arrange them.
How many different ways can you arrange the letters of the word chocolate?
chocolate = 9 letters, where o and c are repeated 2 times. There are 9!/(2!2!) = 90,720 ways.
How many distinguishable ways can you arrange the letters aaabb?
To find the number of distinguishable arrangements of the letters "aaabb," we use the formula for permutations of multiset: [ \frac{n!}{n_1! \times n_2!} ] where ( n ) is the total number of letters, ( n_1 ) is the number of indistinguishable letters of one type, and ( n_2 ) is the number of indistinguishable letters of another type. Here, ( n = 5 ) (total letters), ( n_1 = 3 ) (for 'a'), and ( n_2 = 2 ) (for 'b'). Calculating this gives: [ \frac{5!}{3! \times 2!} = \frac{120}{6 \times 2} = \frac{120}{12} = 10 ] Thus, there are 10 distinguishable ways to arrange the letters "aaabb."
How many times can the word fancy be arranged?
The word "fancy" consists of 5 distinct letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
What are the ways you can arrange the letters in banana?
The word "banana" consists of 6 letters, with the letter "a" appearing 3 times, "n" appearing 2 times, and "b" appearing once. To find the number of unique arrangements, you can use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2! \times n_3!} ), where ( n ) is the total number of letters, and ( n_1, n_2, n_3 ) are the counts of each distinct letter. This gives ( \frac{6!}{3! \times 2! \times 1!} = 60 ) unique arrangements of the letters in "banana."
How manny times has Canada hosted the Olympics?
3 times
How manny times does 2 go into 168?
84 times.
