6
25 times
36 times
24 times
There are 720 possible permutations.
There are 6 letters so there are 6P6 or 720 ways to arrange them. They don't all make a real word though.
5 x 4 x 3 x 2 = 120 different ways to arrange them.
chocolate = 9 letters, where o and c are repeated 2 times. There are 9!/(2!2!) = 90,720 ways.
To find the number of distinguishable arrangements of the letters "aaabb," we use the formula for permutations of multiset: [ \frac{n!}{n_1! \times n_2!} ] where ( n ) is the total number of letters, ( n_1 ) is the number of indistinguishable letters of one type, and ( n_2 ) is the number of indistinguishable letters of another type. Here, ( n = 5 ) (total letters), ( n_1 = 3 ) (for 'a'), and ( n_2 = 2 ) (for 'b'). Calculating this gives: [ \frac{5!}{3! \times 2!} = \frac{120}{6 \times 2} = \frac{120}{12} = 10 ] Thus, there are 10 distinguishable ways to arrange the letters "aaabb."
The word "banana" consists of 6 letters, with the letter "a" appearing 3 times, "n" appearing 2 times, and "b" appearing once. To find the number of unique arrangements, you can use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2! \times n_3!} ), where ( n ) is the total number of letters, and ( n_1, n_2, n_3 ) are the counts of each distinct letter. This gives ( \frac{6!}{3! \times 2! \times 1!} = 60 ) unique arrangements of the letters in "banana."
3 times
84 times.
You can arrange and rearrange the word as many times as you like!There are 5040 different ways.