24 without repeating digits: 4702 4720 4072 4027 4270 4207 7402 7420 7042 7024 7240 7204 0472 0427 0742 0724 0247 0274 2470 2407 2740 2704 2047 and 2074.
There are 9C3 = 84 combinations.
9
There are 5,040 combinations.
45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
Oh, what a happy little question! There are 100,000 different 6-digit combinations that can be made from 0 to 99. It's like painting a beautiful landscape with numbers - each combination is unique and special in its own way. Just imagine all the possibilities and let your creativity flow!
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
I believe the answer would be 10^9 or 1,000,000,000