"Permutations" do consider the order. If you want the order ignored, then you're looking for "combinations". 3-digit permutations, repetition allowed: 9 x 9 x 9 = 729 3-digit permutations, no repetition: 9 x 8 x 7 = 504 3-digit combinations, no repetition = 504/6 = 84.
To calculate the number of 9-digit combinations that can be made from the numbers 1-9 without repetition, we use the permutation formula. Since there are 9 numbers and we are choosing 9 without repetition, the formula is 9P9 = 9! / (9-9)! = 9! / 0! = 9! = 362,880. Therefore, there are 362,880 9-digit combinations that can be made from the numbers 1-9.
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.
10! permutations of the word "Arithmetic" may be made.
There are 7893600 permutations.
There are 5,273,912,160 permutations of 5 numbers out of 90.
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There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
2520
All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you. The number of combinations is 9C3 = 9*8*7/3*2*1 = 84
The number of permutations of three numbers if any number can be repeated is 27 times (Formula is n3, i.e. 33, which is 3 x 3 x 3)333336339363366369393396399633636639663666669693696699933936939963966969993996999