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Given the individual digits: 4, 6, 9, 1, and 3,

the number of 4-digit permutations is (5! / 1!) = (5 x 4 x 3 x 2) = 120 .

The number of combinations is [ 5! / (1!4!) ] = 5 .

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Q: How many 4 digit permutations and combination can be made from 46913?
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