All the numbers from 0 to 999 so 1000 numbers
However if you mean only using each number once the answer is about 720
* * * * *
No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you.
The number of combinations is 9C3 = 9*8*7/3*2*1 = 84
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Just 1.
Any 5 from 59 = 5006386
If the same 7 digits are used for all the combinations then n! = 7! = 7*6*5*4*3*2*1 = 5040 combinations There are 9,999,999-1,000,000+1=9,000,000 7-digit numbers.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 5,461,512 such combinations.
It is: 9C7 = 36
10,000
15
6 ways: 931,913,139,193,391,319
Oh, dude, you're hitting me with the math questions, huh? Alright, so to find the number of 5-digit combinations from 1 to 20, you just do 20^5, which is like 3,200,000. So, yeah, there are 3,200,000 possible 5-digit combinations from 1 to 20.
There are 840 4-digit combinations without repeating any digit in the combinations.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
Just 1.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.