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How many even 3-digit numbers can be formed from the digits 1 2 5 6 9 if each digit can be used only once?
24 of them. So we have a 2 or 6 in the unit position, therefore (2)(4)(3) = 24 even three-digit numbers, can be formed.
How many 5 digit combinations for numbers 1- 25?
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
How many 5 digit numbers can be formed out of 56789 if they can be repeated?
Five numbers (5, 6, 7, 8, 9) can be selected for each of the 5 digits. So, there are 5*5*5*5*5 or 55 or 3125 five digit numbers.
How many 3 digit numbers can be formed from the digits 357 with any digit repeated?
27 three digit numbers from the digits 3, 5, 7 including repetitions.
How many even numbers of four digits can be formed with digits 1 2 3 4 5 6 repetition of the digit is allowed?
6 x 6 x 6 x 3 = 648 6 because the first digit can be any of the numbers 6 again, because the second digit can be any of the numbers 6, again, because the third digit can be any of the numbers 3, because the fourth/last digit can only be 2, 4, or 6
How many even two digit numbers are there where the sum of the digits is 5?
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
How many 5 digit numbers are divisible by 150?
There are 600 5-digit numbers divisible by 150.
How many 5 digit numbers are odd?
The first 5 digit number is 10,000 and the last is 99,999. Thus there are 90,000 numbers between that range. Half of them are odd & half are even. 45,000 each
How many two-digit numbers has a digit sum equal to 5?
There are five such numbers.
How many even 3-digit positive integers can be written using the digits 1 3 4 5 and6?
If a digit can be repeated there are 5 x 5 x 5 = 125 possible numbers If a digit cannot be repeated there are 5 x 4 x 3 = 60 possible numbers.
How many 5 digit numbers are there?
There are 9000 of them.
How many 3-d How many 3-digit numbers will be there which are divisible by 19igit numbers with atleast one 5 in their digits?
None. 3 digit numbers are not divisible by 19 digit numbers.
What is the highest 5 digit even number to be made out of 0123456789?
If the numbers are not repeated then the highest 5 digit even number to be made out of 0123456789 is : 98764.
How many 5 digits are there?
There are 90000 5-digit numbers.
How many positive even integers up to 1000 inclusive have an even digit sum?
For single digit numbers in the range 0-9 there are 4 (excludes zero). For 2 digit numbers in the range 10-99, then the even sum condition only applies when both digits are even, i.e. such numbers ending in 0,2,4,6,8 in the 20s, 40s, 60s & 80s. There are 4 x 5 = 20. For 3 digit numbers in the range 100-999 then the even sum condition applies when (1) All 3 digits are even or (2) The first 2 digits are odd and the third digit is even. (1) There are 4 options for the 1st digit (2,4,6,8), and 5 options for the 2nd and 3rd digits (0,2,4,6,8) There are thus 4 x 5 x 5 = 100 qualifying numbers. (2) If the 1st and 2nd digits are odd and the 3rd digit is even then there are 5 x 5 x 5 = 125 qualifying numbers. Total number of qualifying numbers = 4 + 20 + 100 + 125 = 249
How many three digit even numbers are possible if the leftmost digit cannot be zero?
To find the number of three-digit even numbers where the leftmost digit cannot be zero, we consider the structure of a three-digit number represented as (ABC), where (A) is the leftmost digit, (B) is the middle digit, and (C) is the rightmost digit. The leftmost digit (A) can be any digit from 1 to 9 (9 options), the middle digit (B) can be any digit from 0 to 9 (10 options), and the rightmost digit (C) must be an even digit (0, 2, 4, 6, or 8, giving 5 options). Thus, the total number of three-digit even numbers is (9 \times 10 \times 5 = 450).
