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How many 6 digit numbers are there that do not have the number 5 in?
Wiki User
∙ 14y ago
The first digit can be any one of 8. (all except '0' and '5')
The second, third, fourth, fifth, and sixth digit can be any one of 9. (all except '5')
The total number of possible permutations is (8 x 9 x 9 x 9 x 9 x 9) = 472,392
Wiki User
∙ 14y ago
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How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 5 digit numbers can be made with the numbers 1 2 0?
The first digit can by selectd in one of two ways, since a number starting with zero would not be a 5-digit number. After that, each of the other four digits can be selected in 3 ways. So the number of 5-digit numbers is 2*34 = 162
How many 5 digit numbers are divisible by 150?
There are 600 5-digit numbers divisible by 150.
How many 5-digit whole numbers can be made with the number 0 1 2?
59
What are some 5-digit numbers that are divisible by 4 and 9?
Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 2 digit numbers are divisible by 5?
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many two digit numbers are divisible by either 3 or 5?
How many two digit number are divisible by 5
How many 3 digit number are divisible by 5?
There are 180 3-digit numbers divisible by five.
How many Three Digit Numbers are Divisible by BIN-10001?
A three digit number cannot be divisible by a 5 digit number - in any base.
How many positive prime numbers have a ones digit of 5?
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
How many 5 digit numbers can be made with the numbers 1 2 0?
The first digit can by selectd in one of two ways, since a number starting with zero would not be a 5-digit number. After that, each of the other four digits can be selected in 3 ways. So the number of 5-digit numbers is 2*34 = 162
How many 5 digit combinations for numbers 1- 25?
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
How many 5 digit number are there in all?
89999 5-digit numbers are there in all... That is the numbers from 10000 to 99999... Wrong. There are 90000 five digit numbers in all. When you start to count you count from 10001 to 99999which is 89999 numbers. To that you add the one number 10000. 89999+1=90000
How many 5 digit numbers are divisible by 150?
There are 600 5-digit numbers divisible by 150.
How many 5-digit numbers can be made only using the numbers 1 2 3 4 5 with out repeating a number twice example 12345 12354 12435?
120 5-digit numbers can be made with the numbers 12345.
