Q: How many 6 number combinations are there in numbers 1 tp 50?

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The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700

506 = 15,625 million

The number of combinations of 50 things taken 5 at a time is (50! - 45!) / 5! or 2,118,760, so the probability of winning the lottery on 1 ticket by picking 5 numbers out of 50 numbers is 1 in 2,118,760, or 0.00000047197. More formally, the number of combinations of N things taken P at a time is (N! - (N-P)!) / P!

51

Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)

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The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700

506 = 15,625 million

We are not told anything about repeats so I will assume you can repeat a digit. For example, you can have 111111 The first digits has 50 choices so does the second and the third..etc so we have 50^6 combinations.

There are many such combinations. 1 x 50 for instance.

50 to the 5th power.156,250 combination.

5 digit combinations for numbers 1 to 50= 50 C 5N!= 1x2x3x4x...x (N-1) x N= (50!)/(45!x5!) =(50x49x...x2x1)/((45x44x...x2x1)(5x4x3x2x1))=(50x49x48x47x46)/(5x4x3x2)=254251200/120 =21187602118760 combinations

There is only one number that is equal to 103. It's the number 103.Obviously there are many combinations of two numbers which add up to 103. Try 100 + 3, or 50 + 53.

There are many combinations possible The most popular combination is 2,3,5,17,23.

Looks like here you should be using the equation for a combination rather than a permutation because order does not matter. Here is the equation for combinations: nCr = n!/(r!*(n-r)!) where n= the total number being chosen from (50) and r= the number that can be chosen at one time (5). 50C5 = 50!/(5!*(50-5)!) -> 50C5= 2118760. There are 2118760 ways to choose 5 numbers from the numbers 1-50.

The number of combinations of 50 things taken 5 at a time is (50! - 45!) / 5! or 2,118,760, so the probability of winning the lottery on 1 ticket by picking 5 numbers out of 50 numbers is 1 in 2,118,760, or 0.00000047197. More formally, the number of combinations of N things taken P at a time is (N! - (N-P)!) / P!

51

Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)