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38.2C-24.5C = 13.7 C change

this requires 13.7 calories per gram or 1370 calories total

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Q: How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?
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How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?

1370 calories


If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?

To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.


How many calories are required to raise 8 grams of water 7 degrees Celsius?

700


If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?

105C


How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?

(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?

one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius


How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?

46 calories (or 192, 464 joules) for each Celsius degree.


How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?

21 grams through 71 degrees is 21x71 calories.


The amount of dietary Calories in one hard-boiled egg could raise the temperature of?

1,000 grams of water by 75 degrees Celsius


How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams for 0.0?

46 calories (or 192, 464 joules) for each Celsius degree.


How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?

q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories