There are 46C5 = 46*45*44*43*42/(5/4/3/2/1) = 1,370,754 of them and I am not stupid enough to try and list them. You are welcome to try, though.
If you are using three distinct numbers and want to find the number of different combinations that can be formed, you would consider the combinations of those numbers. For three numbers, the combinations can be represented as C(3, k) for k = 1 to 3. Thus, the total combinations are 3 (for k=1) + 3 (for k=2) + 1 (for k=3), resulting in a total of 7 unique combinations.
There are twelve possible solutions using the rule you stated.
120 different combinations (5 x 4 x 3 x 2).
The number of combinations of 4 numbers that can be made from a set of 36 numbers without repeating any numbers is calculated using the combination formula. The formula for combinations is nCr = n! / r!(n-r)!, where n is the total number of options and r is the number of selections. In this case, n = 36 and r = 4. Therefore, the number of combinations is 36! / 4!(36-4)! = 36! / 4!32! = (36 x 35 x 34 x 33) / (4 x 3 x 2 x 1) = 58905 combinations.
24680
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.
The number of combinations, denoted by 11C6 is 11!/[6!*(11-6)!] = 11*10*9*8*7/(5*4*3*2*1) = 462
1,023,456,789
If you are using three distinct numbers and want to find the number of different combinations that can be formed, you would consider the combinations of those numbers. For three numbers, the combinations can be represented as C(3, k) for k = 1 to 3. Thus, the total combinations are 3 (for k=1) + 3 (for k=2) + 1 (for k=3), resulting in a total of 7 unique combinations.
From 1 to 20, you can pull out 15,504 different groups of 5 numbers, and each group can be lined up in 120 different orders.
Including the leading zero, then the answer is 210. Or, allowing for repeating numbers, 10000.
9,876,543,210 9876543210
9875.
There are twelve possible solutions using the rule you stated.
120 different combinations (5 x 4 x 3 x 2).
To find all the combinations of the numbers 1204 without repeating any number, we can use the formula for permutations without repetition. There are 4 digits in the number 1204, so there are 4 factorial (4!) or 24 possible combinations. These combinations would include 1204, 1240, 1024, 1042, 1402, 1420, 2104, 2140, 2014, 2041, 2401, 2410, 4012, 4021, 4102, 4120, 4201, 4210, 1024, 1042, 1204, 1240, 1402, 1420.