That will completely depend on how much water there is.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
It depends on what temperature is is at and how much water there is.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
21 grams through 71 degrees is 21x71 calories.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
Any number of joules, no matter how small, will raise the temperatureof the water. The total number required in order to accomplish the jobdepends on the final temperature you want to see. The higher that is,the more energy it will take to reach it.
212 degrees F, 100 degrees C is the temperature at which water boils
Water at room temperature will have 25 degrees Celsius. For all intensive purposes standard room temperature is considered at 25 degrees. This temperature is of very importance when studying thermochemistry.
That's going to depend on how much water you're responsible for. Teacup at 60 degrees . . . very few BTU. Swimming pool at 60 degrees . . . many more BTU. It's also going to depend on whether you're talking about Celsius or Fahrenheit degrees. Fahrenheit degrees . . . fewer BTU. Celsius degrees . . . more BTU. (Also, the water will escape as you pass 100.) In general, one BTU is approximately the energy required to raise the temperature of 1 pound of water 1 degree Fahrenheit. You can take it from there, when you reach the job site and determine the exact scope of the work.
6100 calories It takes 10 calories to raise the 10 grams of water each degree celsius. So, a temperature change of 70 degrees celsius requires 700 cal. 540 cal/g x 10g=5400 cal 5400 cal + 700 cal= 6100 calories
How much water? What is the gas used?
Q=mcÎ”T Q=14 x 4200 x 21.6 Q=1270080J
The amount of energy required to raise the temperature of 1 gram of pure water by 1 degree C varies as the temperature varies but its average value is 4.184 Joules. So, to raise the temp of 2.8 kg = 2800 grams of water by 8 deg C = 4.184*2800*8 = 93,721.6 Joules or 93.7 kJ.
In Fahrenheit the freezing temperature is 32 degrees. negative three degrees would be 35 degrees below freezing.