12oC
(Explanation): use the equation and substitue known values to find change in temperature. 340=(6.8)(4.186)(^T) ^T= 11.9445... or rounded to 12 degrees C
300
25
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
That depends on the starting temperature of the cold water and the starting temperature of the hot water.
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
That will completely depend on how much water there is.
12 degrees Celsius
12 degrees Celsius
15480.80
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
21 grams through 71 degrees is 21x71 calories.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
15.37684 joules
It depends on what temperature is is at and how much water there is.