36
It is 18 diagonals
5
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
17
In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.
98
7-3 = 4
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
In a 100-sided polygon, if diagonals are drawn from one vertex, they connect to all non-adjacent vertices. A vertex connects to 97 other vertices (100 total vertices minus the 1 vertex itself and the 2 adjacent vertices). The number of triangles formed with the diagonals from that vertex is given by the formula for combinations, specifically ( \binom{97}{2} ), which equals 4,656 triangles.
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
In a polygon with ( n ) sides, the number of diagonals that can be drawn from one vertex is given by the formula ( n - 3 ). For a polygon with 35 sides, this means you can draw ( 35 - 3 = 32 ) diagonals from one vertex. Thus, from one vertex in a 35-sided polygon, you can draw 32 diagonals.