There are 7!/(3!*2!) = 420 ways.
7! for the seven letters in "success", but
The answer is 5!, 5 factorial. This equals 5 X 4 X 3 X 2 X 1, which is 120.
(!7)/(!2.!2) =1260
You have eight letters to work with, and can use any four of them, but only once per combination. That means that the total number of possible combinations you can make is: 8! / (8 - 4)! = 8! / 4! = 8 * 7 * 6 * 5 = 1680 So there are 1680 possible combinations.
The answer depends on how many letter tiles you have and which letters are on those tiles.
tak-kee plasstic compnany prints a 2-letter code on each of its products. How many different 2-letters codes can be formed using the 26 letters of the alphabet if the two letters must be different?
240
Algorithm is the only nine letter word.
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
120
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
720 (6 x 5 x 4 x 3 x 2)
8 different 4-letter words can be formed from the letters of the word "Nation".
20! = 2432902008176640000
Words that can be made with the letters in 'gazebo' are:aageagobagbebegboabogegogabgazegogob
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
The answer is 5!, 5 factorial. This equals 5 X 4 X 3 X 2 X 1, which is 120.
6*5*4*3*2*1=720