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This is a question involving permutations and possibilities.Nine numbers, four slots to fill, and I'll assume no duplicates for now.


9!/(4!(9-4)!)

= 6*7*8*9 / 24

= 7*8*9 / 4

= 7*2*9

= 63*2

= 126


There are 126 unique four-digit numbers that can be arranged with the digits 1-9.


If duplicates were allowed, there would be 94possibilities, or 6,561.

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Q: How many different four digit numbers can you make with 1 2 3 4 5 6 7 8 9 if so what are they?
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