Since each of the digits 0, 1, 2, and 3 is unique you can have 4! (4 factorial) possible combinations:
4! = 4x3x2x1 = 24 different ways to arrange the 4 digits
Of course any number starting with zero would usually be truncated to 3 digits.
In that case you would omit all those arrangements from the list of four-digit numbers leaving you with 3x3x2x1 = 18 possibilities
1) 1023
2) 1032
3) 1203
4) 1230
5) 1302
6) 1320
7) 2013
8) 2031
9) 2103
10) 2130
11) 2301
12) 2310
13) 3012
14) 3021
15) 3102
16) 3120
17) 3201
18) 3210
3 options for the first digit (since I am assuming the number won't start with a zero), 3 for the second, 2 for the third, 1 for the fourth. Multiply everything together.
how make the answer im don/now
how make the answer im don/now
18 (and 6 more starting with a 0).
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundredβs place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
100000 - including numbers with leading 0s
99999
how make the answer im don/now
18 (and 6 more starting with a 0).
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
how make the answer im don/now
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundredβs place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
If the digits are all different then 18. Otherwise, 192.
12 numbers.
36
10,000
100000 - including numbers with leading 0s
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
99999