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Q: How many different numbers can be formed by rearranging the four digits in 2013?

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18 (and 6 more starting with a 0).

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.

If the digits are all different then 18. Otherwise, 192.

Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.

12 numbers.

36

10,000

99999

100000 - including numbers with leading 0s

Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.

Assuming they are non-zero and different, the answer is 6.

192, including ones containing repeat digits.

There are 5*4*3 = 60 such numbers.

There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.

24

500

6 if you don't repeat any.

840

There are 60480 numbers.

If they can be repeated, 343 different numbers. If they can be used once each, there are only 210.

24 different numbers.

If the digits may not be repeated, there are 6x5x4x3x2x1 = 720 numbers, If digits can be repeated, the answer is 6x6x6x6x6x6 = 46,656 numbers If zero is ong the available digits but is excluded from the first place. 5x6x6x6x6x6=38,880 numbers

1 set

It is 120 if the digits cannot be repeated.

There are 3024 of them.