15
6, as long as they are all different
6 if all digits are different, 27 otherwise.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
about... 25 just take 5 numbers times 5 numbers
Using the digits 1, 3, and 5 exactly once, you can create different 3-digit numbers by permuting these digits. The number of permutations of 3 distinct digits is calculated as 3! (3 factorial), which equals 6. Therefore, the different numbers you can create are: 135, 153, 315, 351, 513, and 531. Thus, there are 6 different numbers that can be formed.
6, as long as they are all different
If the only operation is addition, then 3.
6 if all digits are different, 27 otherwise.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
There are two different numbers. 3 and 7
48
about... 25 just take 5 numbers times 5 numbers
120
If you want 4-digit numbers, there are 24 of them.
1000
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
256!