There are three that I can see, there's clip, board and lip.
There are 8P5 = 8*7*6*5*4 = 6720
(!7)/(!2.!2) =1260
The answer depends on how many letter tiles you have and which letters are on those tiles.
tak-kee plasstic compnany prints a 2-letter code on each of its products. How many different 2-letters codes can be formed using the 26 letters of the alphabet if the two letters must be different?
12
There are 5*4*3 = 60 permutations.
9*8*7 / 2! / 3!
nkhnlk453
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
There are 8P5 = 8*7*6*5*4 = 6720
There are ten letters BUT there are 3 Ss and Ts and 2 Is. So the answer is 10!/(3!*3!*2!) = 50400
A - Z means you can use the whole alphabet, which usually contains 26 letters. So a one-letter code would give you 26 permutations. 2 letters will give you 26 x 26 permutations. A three letter code, finally, will give you 26 x 26 x 26 , provided you don't have any restrictions given, like avoiding codes formed from 3 similar letters and such.
420.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
8 different 4-letter words can be formed from the letters of the word "Nation".